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Lcars85296
Small-Cap Auctioneer
Joined: 17 Mar 2005
Posts: 17
Location: Arizona
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 Posted: Wed May 04, 2005 8:26 am Post subject: B1.3m-3a --Ratings sql error |
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After a sale when you try to post a rating I am getting:
Couldnt insert rating
DEBUG MODE
SQL Error : 1064 You have an error in your SQL syntax near ' 3, ' at line 9
INSERT INTO phpbb_auction_user_rating (FK_auction_offer_id, FK_auction_offer_seller_id, FK_auction_offer_buyer_id, auction_offer_seller_rating_text, FK_auction_offer_seller_rating_id, auction_user_seller_rating_time) VALUES(73, , 3, 'duper', '1', 1115193570)
Line : 177
File : auction_rating.php
It is not adding the value " . $seller_id . ",
I have checked the code for the sql to retreive to $seller_id and it looks good to me. I have run out of ideas why the $seller_id is not set. The $buyer_id is called from the same sql and seems to be fine. Any ideas?
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"A witty saying proves nothing."
- Voltaire (1694-1778) |
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FR
Site Admin
Joined: 26 Jan 2004
Posts: 1764
Location: root directory
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| Posted: Wed May 04, 2005 7:03 pm Post subject: |
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OPEN auction_rating.php
FIND
| Code: | if( isset($HTTP_GET_VARS[POST_AUCTION_OFFER_URL]))
{
$auction_offer_url = ( isset($HTTP_GET_VARS[POST_AUCTION_OFFER_URL]) );
$auction_offer_url = htmlspecialchars($auction_offer_url);
}
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REPLACE WITH
| Code: | if( isset($HTTP_GET_VARS[POST_AUCTION_OFFER_URL]))
{
$auction_offer_url = $HTTP_GET_VARS[POST_AUCTION_OFFER_URL];
$auction_offer_url = htmlspecialchars($auction_offer_url);
}
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FIND
| Code: | $user_id = ( isset($HTTP_GET_VARS[POST_USERS_URL]) );
$user_id = htmlspecialchars($user_id);
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REPLACE WITH
| Code: | $user_id = $HTTP_GET_VARS[POST_USERS_URL];
$user_id = htmlspecialchars($user_id);
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Lcars85296
Small-Cap Auctioneer
Joined: 17 Mar 2005
Posts: 17
Location: Arizona
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| Posted: Thu May 05, 2005 6:25 am Post subject: |
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That worked great.
Thanks
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